(1/16)x^2-4x+20

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Solution for (1/16)x^2-4x+20 equation: 


x in (-oo:+oo)

(1/16)*x^2-(4*x)+20 = 0

(1/16)*x^2-4*x+20 = 0

1/16*x^2-4*x+20 = 0

DELTA = (-4)^2-(1/16*4*20)

DELTA = 11

DELTA > 0

x = (11^(1/2)+4)/(1/16*2) or x = (4-11^(1/2))/(1/16*2)

x = 8*(11^(1/2)+4) or x = 8*(4-11^(1/2))

x in { 8*(4-11^(1/2)), 8*(11^(1/2)+4) }

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